Calculating Energy Delivered by a Pacemaker

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SUMMARY

The discussion focuses on calculating the energy delivered by a pacemaker with a resistance of 100 ohms, a pulse amplitude of 1.2 volts, and a pulse duration of 0.5 milliseconds at a stimulation rate of 70 beats per minute. The calculated power is 0.0144 watts, leading to an energy delivery of 7.2 microjoules per pulse. The current drain of 2 microamps is clarified as related to battery consumption rather than affecting the energy calculation directly. The final output indicates that the pacemaker operates at a power level of 8.4 microwatts, suggesting a minimum battery voltage requirement of 4.2 volts.

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  • Understanding of basic electrical concepts such as voltage, current, and resistance.
  • Familiarity with the formula for calculating power (P = V^2/R).
  • Knowledge of energy calculations (Energy = Power × Time).
  • Basic concepts of pacemaker functionality and operation.
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  • Research the principles of electrical circuits in biomedical devices.
  • Learn about the specifications and operational characteristics of pacemakers.
  • Explore the implications of current drain on battery life in medical devices.
  • Investigate advanced energy calculation methods for implantable medical devices.
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Biomedical engineers, medical device designers, students studying electrical engineering, and healthcare professionals interested in the operational mechanics of pacemakers.

Sloan650
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A pacemaker stimulates heart tissue with R of 100ohms.
Pulse amplitude is 1.2 Volts & pulse duration is 0.5ms.
Stimulates at 70bpm
Current drain = 2microamps

Calculate energy delivered to heart from pacemaker at each pulse.

i got

P=V^2/R = 0.0144

Then Energy = Power*time = 0.0144*0.5x10-3 = 7.2x10-6 J

But do i not need to take into account the current drain?
 
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power P = V X I

and since I = V/R,
then
P= V X (V/R) = V^2/R

so when you did V^2/R you included current.

the 2 microamps sounds more like battery drain to me.

7.2 microjoules 70 times a minute = 8.4 microwatts
at 2 microamps dictates least 4.2 volt battery?

anything corroborate here?
 
2µA - It is current drain due to the pacemaker circuitry.

Im a bit confused, its a past exam question.
 
all the values i gave were all that was given in the question.
 

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