Calculating Energy of Electron with T=0.0017

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Homework Help Overview

The discussion revolves around calculating the energy of an electron incident on a potential energy barrier, characterized by a height of 5.4 eV and a thickness of 0.73 nm, given a transmission coefficient of 0.0017. Participants are exploring the relationship between these parameters in the context of quantum physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formula for the transmission coefficient and its dependence on the barrier height and electron energy. There are inquiries about the specific figure referenced and the method used to arrive at a particular answer of 0.203 eV.

Discussion Status

Some participants are seeking clarification on the problem setup and the relevant equations, while others are encouraging the original poster to share their attempts at a solution to facilitate further guidance. There is an acknowledgment of the need for assistance without a clear consensus on the correct approach yet.

Contextual Notes

Participants note that the figure mentioned is not available for discussion, and there is uncertainty regarding the calculations leading to the proposed energy value. The original poster expresses difficulty in solving the problem despite having set up the equations.

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Consider a potential energy barrier like that of Fig. 38-15 but whose height U0 is 5.4 eV and whose thickness L is 0.73 nm. What is the energy of an incident electron whose transmission coefficient is 0.0017?

I tried to solve the problem my self but could not get the right answer still having trouble with this question please let me help with this my answer is .203 but not right if some one help me out with this questino and tell me the answer would appreciate that ! thank you very one here are the hint !

The transimission coefficient for a barrier of height U0 and width L is given by
T = e-2bL ...1
Where b = v (8p2m(U0 - E ) / h2 ) ...2
Substituting values in equation (1) we get b
Then substitute b in equation (2) we get E
Givem that U0 = 5.4 eV
m = mass of electron
L = 0.73 nm
T = 0.0017
I hope this may help you.
 
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Quntum physics ! barrier energy !

Consider a potential energy barrier like that of Fig. 38-15 but whose height U0 is 5.4 eV and whose thickness L is 0.73 nm. What is the energy of an incident electron whose transmission coefficient is 0.0017?

I tried to solve the problem my self but could not get the right answer still having trouble with this question please let me help with this my answer is .203 but not right if some one help me out with this questino and tell me the answer would appreciate that ! thank you very one here are the hint !

The transimission coefficient for a barrier of height U0 and width L is given by
T = e-2bL ...1
Where b = v (8p2m(U0 - E ) / h2 ) ...2
Substituting values in equation (1) we get b
Then substitute b in equation (2) we get E
Givem that U0 = 5.4 eV
m = mass of electron
L = 0.73 nm
T = 0.0017
I hope this may help you.
 
What is fig 38-15? =P

and how did you do to get your answer 0.203 ?
 
don;t worry about the figure ? its in the book i cannot tell you the right here but has nothing to do with the answer .. acutally .203 i just plugin the values but i am sure i am not right so please help me out i already set up the equation but still getingg problem to solve this problem !or to find of the energy ..
 
It is straightforward, trivial. You have all values except one right?

Why don't you post your attempt to solution so that we may put you in the right direction instead?
 

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