Calculating Entropy Changes in a Rigid Tank with Argon at Different Temperatures

[cmilho10]

A rigid tank of small mass contains 50.0 g of argon, initially at 200°C and 100 kPa. The tank is placed into a reservoir at 0°C and is allowed to cool to thermal equilibrium. Calculate the following:
(a) the volume of the tank
(b) the change in internal energy of the argon
(c) the energy transferred by heat
(d) the change in entropy of the argon
(e) the change in entropy of the constant-temperature bath

I got the volume of the tank from PV=nRT to be 49.2 L which is correct

change in entropy=dQr/T

Change in Eint=Q-W

I'm not sure where to go from here because I do not know how to find the final temperature of the argon.

 

[fargoth]

you stated in your question that you let it cool to 0 degrees... i think that's the final temprature of the argon...

 

[cmilho10]

It says that the reservoir is at 0 degrees, so I didn't think that would necessarily be the final temperature of the argon cause I thought some of the heat from the argon would be exchanged as well...but maybe I am totally wrong here

 

[abszero]

If it's a thermal reservoir, then the temperature is assumed to remain constant.