Calculating exit velocity of a projectile

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An experiment was conducted using an air cannon to measure the drag on a cylindrical projectile, but the absence of light gates left the velocity measurement uncalculated. The experimenter seeks assistance in calculating the exit velocity using known dimensions, time of flight, air pressure, and launch angle. A suggested method involves using the range equation, which relates initial velocity to the range and launch angle. However, caution is advised as standard projectile equations assume no drag, which could lead to significant errors if drag is present. Accurate calculations must consider both the drag within the cannon and the flight drag after the projectile exits.
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I did an experiment using an air cannon to find the drag exhibited on a cylindrical projectile using different mass/density and pressure/velocity. However, I was not able to obtain light gates at the time, so now I have no measurement for velocity. This is necessary for my results, and I was wondering if anyone could help me in calculating it. I have all dimensions and volumes of the components to the air cannon and projectile, distance and time of flight of the projectile, air pressure within the gas chamber and launch angle. If anyone could help me calculate the exit velocity of the projectile it would be greatly appreciated.
 
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im assuming when you say distance that's the range the projectile has gone? if so and you also have the angle then you can use the basic range equation to find the intial velocity.

range = ((v^2)(sin (2*angle)))/gravity
so
v=sqrt((range*gravity)/(sin(2*angle)))

sorry if i read your question wrong but I am in a rush also if my equation doesn't look to neat just search for range equation on google
 
By drag, I assume you mean within the cannon itself as opposed to flight drag of the projectile after it exits the cannon. Be careful about using the standard projectile equations to calculate exit velocity based on range and angle. They assume zero drag during flight. Since flight drag is proportional to velocity (or velocity squared I don't remember), you could be introducing unacceptable error into your calcs. Flight drag may nor may not be an actual issue in your case, but you should be aware of it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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