- #36
MichaelTam
- 93
- 6
Sounds like you have not learned dimensional analysis. You should, it's quite easy and very useful.MichaelTam said:So the A must be in two dimension and B is 4 dimension, or A should be 1 dimension and B should be 3 dimension?
[Ag]=LT^{-2}LT^{-2}=L^{2}T^{-4}MichaelTam said:I know, but I find don’t know if 3Ag is in two dimension, and## 4dB^2## is in 4 dimensions respect to time?
The point about using dimensional analysis is that you can check each step. Use 'binary chop'. Start in the middle of your working; if it's ok there go to three quarters of the way , etc.MichaelTam said:So it still incorrect?But where I am wrong...
=MichaelTam said:You mean plus or equal of the symbol?
Congratulations. (Do I get one too?)MichaelTam said:I pass the course!,!,!View attachment 269324