To calculate the grams of Fe2O3 required to react with 0.57 mol of Fe, one must utilize stoichiometry based on the reaction Fe2O3 + 3CO → 2Fe + 3CO2. The molar ratio indicates that 1 mole of Fe2O3 produces 2 moles of Fe. Therefore, 0.57 mol of Fe corresponds to 0.285 mol of Fe2O3. Multiplying this by the molar mass of Fe2O3 (159.69 g/mol) yields approximately 45.5 grams of Fe2O3 needed for the reaction.
PREREQUISITESChemistry students, chemical engineers, and professionals involved in materials science or chemical manufacturing will benefit from this discussion.
Have you any thoughts of your own?toughguy said:How can you calculate how many grams of Fe2O3 must react with 0.57 mol of Fe when given the formula:
Fe2O3 + 3CO = = = => 2Fe + 3CO2