Calculating Final Composition of Compounds in Haber's Process with 50% Yield

In summary: So, in summary, in the Haber process, 30 litres each of N2 and H2 are used with a 50% yield. This results in 20 litres of NH3 produced, with 15 litres of H2 and 25 litres of N2 remaining.
  • #1
Suyash Singh
168
1

Homework Statement


30 litres of N2 and 30 litres of H2 are taken in Habers process with 50% yield.What is the final composition of the compunds in litres?

Homework Equations


N2+3H2->2NH3

The Attempt at a Solution


N2 + 3H2-> 2NH3
intial: 30 30 0
final: 30 - x/2 30-(3x)/2 (2x)/2

so,
30 - x/2 + 30-(3x)/2 = (2x)/2

this gives x=20
N2=20L
H2=0L
NH3=20L

Am i right?
 
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  • #2
Suyash Singh said:
so,
30 - x/2 + 30-(3x)/2 = (2x)/2
Why do you expect these two to be equal?

How is the yield defined? Using all hydrogen with just 50% yield is odd.
 
  • #3
mfb said:
Why do you expect these two to be equal?

Howis the yield defined? Using all hydrogen with just 50% yield is odd.
litres are conserved
50 percent yield means half of theoretical value of NH3
 
  • #4
Suyash Singh said:
litres are conserved

2 L of hydrogen plus 1 L of oxygen produce 2 L of gaseous water, 2+1 yields 2, what is conserved here?

Suyash Singh said:
50 percent yield means half of theoretical value of NH3

If only 50% of ammonia was produced, was all the limiting reagent consumed?
 
  • #5
Borek said:
2 L of hydrogen plus 1 L of oxygen produce 2 L of gaseous water, 2+1 yields 2, what is conserved here?
If only 50% of ammonia was produced, was all the limiting reagent consumed?
Ok i understand the limiting concept now.

NH3 produced=2/3 x 30 =20 L

H2 left= 0 L

N2 left= 30- (1/2 x 20) =20 L
 
  • #6
So which one is the limiting reagent here? And how much was left if only 50% reacted?
 
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  • #7
Borek said:
So which one is the limiting reagent here? And how much was left if only 50% reacted?
H2 the limiting reagent

all the elements react only 50 %?
 
  • #8
Suyash Singh said:
H2 the limiting reagent

Right.

all the elements react only 50 %?

Stop guessing, use stoichiometry to calculate.
 
  • #9
Suyash Singh said:
50 percent yield means half of theoretical value of NH3
But you got all of the maximum yield of NH3: You used up all hydrogen.
Based on that you can figure out how much NH3 is produced if you use only half of it.
 
  • #10
NH3 produced = 50/100 x (2/3 x 30) = 10 L
H2 left
= 30 - (3/2 x 10) = 15 L
N2 left
= 30 - (1/2 x 10)= 25 L
 
  • #11
That looks good.
 
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FAQ: Calculating Final Composition of Compounds in Haber's Process with 50% Yield

What is Haber's Process?

Haber's Process is a chemical reaction developed by Fritz Haber in 1909 for the production of ammonia from nitrogen and hydrogen gases. It is a crucial process in the production of fertilizers and other nitrogen-based compounds.

What is the final composition of compounds in Haber's Process with 50% yield?

The final composition of compounds in Haber's Process with 50% yield is 50% ammonia and 50% unreacted nitrogen and hydrogen gases. This means that for every 100 molecules of reactants, 50 molecules of ammonia will be produced.

How is the final composition of compounds calculated in Haber's Process?

The final composition of compounds in Haber's Process is calculated using the stoichiometric ratio of the reactants and products. This is based on the balanced chemical equation for the reaction, which determines the exact amount of each compound that will be produced.

What factors can affect the final composition of compounds in Haber's Process?

The final composition of compounds in Haber's Process can be affected by various factors such as temperature, pressure, and the presence of catalysts. These factors can alter the rate of the reaction and ultimately impact the yield of ammonia.

How can the yield of ammonia be increased in Haber's Process?

The yield of ammonia in Haber's Process can be increased by optimizing the reaction conditions such as temperature, pressure, and the use of catalysts. Additionally, using excess reactants and continuously removing the product from the reaction mixture can also improve the yield of ammonia.

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