Calculating Final Temperature and State When Mixing Ice and Water

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 5K views
DBW3
Messages
1
Reaction score
0

Homework Statement



If you mixed 200g if ice that is at -5°C with 20g of water that is at 15°C, what will be the temperature and condition of the final state once equilibrium is achieved?


Homework Equations


Q=mcΔT, Q=mLf


The Attempt at a Solution


I know that the amount of ice is to great to change with such little water, so I know the final condition will be a 220g block of ice at some temperature between -5°C and 0°C. Since the mass of the water is added to the mass of the ice does this imply that Qgained≠Qlost?

That's what I'm having trouble on, deriving the equation to solve for temperature if they are not equal.
 

Discussion

Physics news on Phys.org
Go ahead with your equations and whatever you know.i shall help you along.
 
Hi DBW, have you considered the phase change involved? :smile: