Calculating Final Velocity with Constant Force

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Homework Help Overview

The discussion revolves around calculating the final velocity of a mass subjected to a constant force, specifically examining two scenarios: one where the mass starts from rest and another where it has an initial velocity in the opposite direction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of Newton's second law and the relationship between force, mass, and velocity. There are attempts to use different formulas to calculate final velocity, and questions arise regarding the directionality of velocity as a vector quantity.

Discussion Status

Some participants have confirmed parts of the calculations while others express uncertainty about their results. There is an ongoing exploration of how to properly account for direction in velocity calculations, with some guidance provided on interpreting vector quantities.

Contextual Notes

Participants note that the teacher has indicated that negative answers are not acceptable, leading to discussions about how to represent direction without using negative signs.

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Homework Statement


A constant force of 4.0 N to the right acts on a 3.0 kg mass for 0.45 s.

a)Find the final velocity of the mass if it is initially at rest.

b)Find the final velocity of the mass if it is initially moving along the x-axis with a velocity of 12 m/s to the left.

Homework Equations



F=p/t

The Attempt at a Solution



okay so for the a i got 0.6 using vf=Ft/m and just plugged in. but for b i don't know what to do..need your help thanks!
 
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First part is correct.

Use the formula F=\frac{mv-mu}{t} where m is mass,v is final velocity and u is the initial velocity and t is time.(Newton's 2nd law)

Also remember that velocity is a vector quantity so you should give a direction when you are stating your answers.
 
ok i used the formula but i have a feeling i calculated it wrong..i got 28 m/s, to the left
 
v=\frac{Ft+mu}{m}

v=\frac{(4*0.45)+3*-12}{3} is that what you did?

which would give you 11.4 ms^{-1} to the left
 
so... -11.4 but my teacher said none of the answers are to be negative so would i still have the same answer but just without a negative sign?
 
Well a vector quantity has both magnitude and direction. So I just took the right as +ve and left as -ve. so the magnitude of the velocity is 11.4ms^-1
 
Thanks! i guess my teacher would just assume left and right without the signs..that was a lot of help!:)
 

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