Calculating Focal Length of a Converging Lens Using Incident and Refracted Rays

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SUMMARY

The discussion focuses on calculating the focal length of a converging lens using the angles of incident and refracted rays. The angles provided are 2.38 degrees for the incident ray and 1.25 degrees for the refracted ray, with a total distance from point A to B of 75.3 cm. The relationship between the object distance (do), image distance (di), and focal length (f) is established using the lens formula: 1/do + 1/di = 1/f. The solution involves applying trigonometric relationships to find do and di based on the tangent of the angles.

PREREQUISITES
  • Understanding of geometric optics principles
  • Familiarity with the lens formula: 1/do + 1/di = 1/f
  • Basic knowledge of trigonometry, specifically tangent functions
  • Ability to interpret diagrams related to optics
NEXT STEPS
  • Study the derivation of the lens formula in optics
  • Learn how to apply trigonometric functions to solve for distances in optics
  • Explore the concept of ray diagrams for converging lenses
  • Investigate the effects of lens curvature on focal length
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Students studying optics, physics educators, and anyone interested in understanding the principles of lens behavior and focal length calculations.

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Homework Statement


The figure illustrates qualitatively a converging lens focusing monochromatic rays from A to B. The vertical and horizontal scales of the figure are not the same. The top ray leaves A at an angle of 2.38 deg above the optic axis and leaves B at an angle of 1.25 deg below the optic axis. The total distance from A to B is 75.3 cm.

http://i32.photobucket.com/albums/d2/NikkiNik88/convLens3.gif

Calculate the focal length of the lens for that light.



Homework Equations



1/d0 + 1/di = 1/f



The Attempt at a Solution



I'm not even sure where to begin when I'm given the angles. I think 75.3 cm = d0 + di
but I'm not sure where to go from there
 
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Hi NikkiNik! :smile:

This is a geometry exercise …

you have two triangles, you know the lengths a+b and h, and you know a/h and b/h. :wink:
 
If AOP is the axis of the lens, and AP and BP are the incident and refracted rays, then OP/do = tan 2.38 and BP /di = tan 1.25.
Or do*tan2.38 = di*tan1.25
And do + di is given.
Find do and di and hence focal length of the lens.
 

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