Calculating Food Value of a Peanut Through Thermodynamics: Efficiency and Joules

  • Thread starter Thread starter ashvuck101
  • Start date Start date
  • Tags Tags
    Thermodynamics
Click For Summary
SUMMARY

The discussion centers on calculating the food value of a peanut using thermodynamics principles, specifically through the equation q=mCt. A 0.5g peanut is burned under 75g of water, raising its temperature from 22 ºC to 40 ºC. Participants clarify that with an efficiency of 40%, the energy transferred to the water represents only a fraction of the total energy released during combustion, necessitating a calculation to determine the total energy output of the peanut.

PREREQUISITES
  • Understanding of thermodynamics principles, particularly heat transfer.
  • Familiarity with the specific heat capacity formula q=mCt.
  • Basic algebra for solving percentage problems.
  • Knowledge of energy efficiency concepts in combustion reactions.
NEXT STEPS
  • Calculate the total energy released by the peanut using the q=mCt formula.
  • Research the concept of energy efficiency in combustion processes.
  • Explore the relationship between mass, temperature change, and energy in thermodynamic systems.
  • Learn about the calorimetry methods used to measure energy content in food.
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, educators teaching calorimetry, and anyone interested in the energy content of food and its measurement through scientific principles.

ashvuck101
Messages
26
Reaction score
0

Homework Statement



6. Cameron burns a 0.5g peanut beneath 75g of water, which increases in temperature from 22 ºC to 40 ºC
a. Assuming 40% efficiency, what is the food value, in J, of the peanut?
b. What is the food value in J per gram?

Homework Equations


q=mCt


The Attempt at a Solution



i just wanted to know does question a mean i take 40% from the calculated joules?
 
Physics news on Phys.org
No, it's not, what it's saying to you is that the energy given off by the peanut to heat up the water is only 40% of the total energy given off in combustion, you need to work out the 100%. (was confused there for a sec :D)
 
No. It means only 40% of the peanut's energy goes into the water
 
what so how am i meant to calulate the other 60% that's not possible?
 
Of course it's possible, that's like me saying to you;

You have 4 apples, which is 40% of the total number of apples from the bag, how many apples were in the bag?
 
er could you put that to me algerbarically please... i mean it makes sense if it was 50% all you do is double it
 
could it be .4x=(Joules calulated)?
 
0.0

From 50% to 100% you times by 2...

From 40% to 100% you times by...

And ^ yes you're right.
 
:smile:
Chewy0087 said:
Of course it's possible, that's like me saying to you;

You have 4 apples, which is 40% of the total number of apples from the bag, how many apples were in the bag?

Beat me to it again.
Although I considered replying earlier
in similar vein I just couldn't bear to do it.

David
 
  • #10
lawl =D
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
17K
  • · Replies 1 ·
Replies
1
Views
1K