Calculating Food Value of a Peanut Through Thermodynamics: Efficiency and Joules

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Homework Help Overview

The discussion revolves around calculating the food value of a peanut using thermodynamic principles, specifically focusing on the efficiency of energy transfer during combustion. The problem involves determining the total energy released by a peanut when burned, given its effect on the temperature of water.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the stated efficiency, questioning how to calculate the total energy based on the given percentage. There are attempts to clarify the relationship between the energy absorbed by the water and the total energy released by the peanut.

Discussion Status

The discussion is active, with participants providing insights into the interpretation of the efficiency concept. Some have offered analogies to clarify the calculation process, while others are seeking further algebraic representation of the problem. There is a collaborative effort to understand the relationship between the energy values.

Contextual Notes

Participants are navigating the constraints of the problem, particularly regarding the efficiency percentage and its impact on the calculations. There is a focus on ensuring clarity in the assumptions made about energy transfer and the total energy output.

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Homework Statement



6. Cameron burns a 0.5g peanut beneath 75g of water, which increases in temperature from 22 ºC to 40 ºC
a. Assuming 40% efficiency, what is the food value, in J, of the peanut?
b. What is the food value in J per gram?

Homework Equations


q=mCt


The Attempt at a Solution



i just wanted to know does question a mean i take 40% from the calculated joules?
 
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No, it's not, what it's saying to you is that the energy given off by the peanut to heat up the water is only 40% of the total energy given off in combustion, you need to work out the 100%. (was confused there for a sec :D)
 
No. It means only 40% of the peanut's energy goes into the water
 
what so how am i meant to calulate the other 60% that's not possible?
 
Of course it's possible, that's like me saying to you;

You have 4 apples, which is 40% of the total number of apples from the bag, how many apples were in the bag?
 
er could you put that to me algerbarically please... i mean it makes sense if it was 50% all you do is double it
 
could it be .4x=(Joules calulated)?
 
0.0

From 50% to 100% you times by 2...

From 40% to 100% you times by...

And ^ yes you're right.
 
:smile:
Chewy0087 said:
Of course it's possible, that's like me saying to you;

You have 4 apples, which is 40% of the total number of apples from the bag, how many apples were in the bag?

Beat me to it again.
Although I considered replying earlier
in similar vein I just couldn't bear to do it.

David
 
  • #10
lawl =D
 

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