Calculating Force on Rectangular Loop from Straight Wire

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A rectangular loop of wire placed next to a straight wire carrying a current of 3.5 A experiences forces due to the magnetic fields generated by both wires. The magnetic field inside the loop is not uniform, leading to cancellation of forces on the loop's own sides. The net force on the loop is determined primarily by the interaction with the straight wire, specifically the forces on the parallel sides of the loop. The right-hand rule indicates that the magnetic forces will act in opposite directions on these sides, resulting in a net force that depends on their relative positions. Ultimately, the calculation of the net force requires considering only the forces acting on the parallel sides of the loop.
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Homework Statement


A rectangular loop of wire is placed next to a straight wire. There is a current of 3.5 A in both wires. Determine the direction and magnitude of the net force on the loop.



Homework Equations


F=BIL


The Attempt at a Solution


I am kinda confused here. Will the rectangular loop feel a force without the straight wire? The current will create a magnetic field inside the loop. Is this field constant everywhere? If so then i believe the forces cancel. Then you just have to find the force on the two vertical sides of the rectangular loop caused by the straight wire.
 
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Fisicks said:

Homework Statement


A rectangular loop of wire is placed next to a straight wire. There is a current of 3.5 A in both wires. Determine the direction and magnitude of the net force on the loop.

Homework Equations


F=BIL

The Attempt at a Solution


I am kinda confused here. Will the rectangular loop feel a force without the straight wire? The current will create a magnetic field inside the loop. Is this field constant everywhere? If so then i believe the forces cancel. Then you just have to find the force on the two vertical sides of the rectangular loop caused by the straight wire.
I do believe the net force acting on the loop caused by its own magnetic field will cancel each other. Using the right hand rule, with the current coing counter-clockwise and looking straight down on it, the magnetic field inside will pointing out of the page, the field outside the loop will point into the page. It won't be uniform due to Biot-Savart's law. However, if one side of the loop is affected by one magnetic force, then the opposite will be affected by an equal but opposite force since they're parallell. The magnetic field produced by the one wire affects the opposite wire by a magnetic force directed out of the loop, and the opposite wire produces it's own magnetic field to affect the other wire with the same force in the other direction. Thus the internal magnetic field of the loop yields zero net force.

To then find the net force acting on the loop caused by the straight wire would depend on the where the straight wire is and the direction of the current in the wire. If the wire's parallell to one side, using the formula for the magnetic force between two parallell wires should yield a suitable answer. You then only need to consider the forces acting on the parallell sides of the loop, since the forces acting on the orthogonal sides would cancel each other out.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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