Calculating Forces in Roof Truss Members for Basic Roof Truss Experiment

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SUMMARY

This discussion focuses on calculating forces in roof truss members for a Basic Roof Truss experiment. The user initially measured deflection in dismantled members under various weights and later assembled the truss at 60-degree angles. Theoretical calculations using the parallelogram method and sine rule indicated that forces Fa and Fb are equal, while Fc should be half of Fa. However, experimental results showed significant discrepancies, prompting the need for further guidance on accurate force calculations.

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  • Understanding of truss structures and their mechanics
  • Familiarity with the parallelogram method for force resolution
  • Knowledge of the sine rule in triangle geometry
  • Basic principles of deflection measurement in structural members
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Structural engineers, civil engineering students, and anyone involved in the design and analysis of truss structures will benefit from this discussion.

CharlesL
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Im doing this problem as a part of the experiment for a Basic Roof Truss. I first started off measuring the deflection for each member of the roof truss (member dismantled from the roof structure) by applying certain amounts of weights. Next I put all the members up into a roof structure as shown in the picture with 60 degrees at each vertex. I am required to find the forces in each of the member thereotically to compare with my experimental results. I am having problems finding the forces in each member thereotically.



The attempt at a solution
In the second diagram,I started by using the parallelogram method and sine rule to find the magnitude of force in member A and B. As a result, Fa and Fb has the same magnitude. Then by using Fa , I used sine rule to obtain Fc as shown in the second diagram. The magnitude of forces i obtain each are about 50% error.
The results i obtain in my experiment shows significant different amount of forces in each member.

Could someone please show me the way to calculate the forces in the members? Thank you in advance.
 

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Yes, Fa and Fb should be equal (in compression), and using the properties of a 30-60-90 triangle, Fc should be 1/2 of Fa (in tension). I don't know what numbers you're getting, and what you are comparing it to in your experimental results. You seem to mention deflection measurements under some load applied to the dismembered members? I don't understand. For theoretical load calculations, you might want to google on "truss method of joints".
 
Yep that was exactly what i got. Fa and Fb as equal and Fc is half of Fa. The deflection measurements are from the dial gauges installed in each member. When they are hung vertically with a load at the bottom, the members tend to stretch and the small amount of stretch is measured as the deflection. Anyway what i go for my experiment shows that Fa and Fb is different as well as Fc. And their difference are by a lot.

Thank you for your help. Appreciate it.
 
Aren't the members of a rigid truss are not supposed to show deflection?
 
shramana said:
Aren't the members of a rigid truss are not supposed to show deflection?
This will make your problem much more difficult.

At first you should ignore this and come up with a rough estimate. Then complete the calculation with the deflections which is tedious. The finite element method is a structured method to solve for the forces in a elegant and structured manner.
 

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