Calculating Frequency of Electron Orbit in Hydrogen Atom

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SUMMARY

The discussion focuses on calculating the frequency of an electron's orbit in a hydrogen atom, given an attractive force of 8.18 × 10-8 N and an orbital radius of 4.57 × 10-11 m. The relevant equations include the centripetal force equation Fc = mv2/r and the circumference of the orbit, represented as 2πr. Participants debated which mass to use in the calculations, prompting clarification on whether to apply the mass of the proton or the electron.

PREREQUISITES
  • Understanding of centripetal force and its application in atomic physics.
  • Familiarity with the concepts of electron orbits and atomic structure.
  • Knowledge of basic physics equations, particularly Fc = mv2/r.
  • Ability to perform calculations involving constants such as π.
NEXT STEPS
  • Study the derivation of the centripetal force equation in atomic systems.
  • Learn about the Bohr model of the hydrogen atom and its implications for electron behavior.
  • Explore the concept of angular frequency and its relation to linear frequency in circular motion.
  • Investigate the significance of using the correct mass (electron vs. proton) in atomic calculations.
USEFUL FOR

Students studying atomic physics, educators teaching quantum mechanics, and anyone interested in the fundamental principles of electron behavior in hydrogen atoms.

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Homework Statement


In a hydrogen atom, the electron in orbit
around the proton feels an attractive force of
about 8.18 × 10−8 N.
If the radius of the orbit is 4.57 × 10−11 m,
what is the frequency in revolutions per second?
Answer in units of rev/s.


Homework Equations


Fc= mv^2/r
(2 pi r)



The Attempt at a Solution


(8.18 x 10^-8) x (4.57 x 10^-11)/ which mass? proton or electron?
pi( 2 x 4.57 x 10^-11)
 
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