Calculating Frequency of Vertical Oscillation for a Spring-Mass System

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SUMMARY

The discussion focuses on calculating the frequency of vertical oscillation for a spring-mass system. The maximum acceleration is derived using the formula a(max) = -w^2 * A, resulting in w^2 = 108, which leads to a frequency of 1.65 Hz. The amplitude is clarified to be half the distance between the highest and lowest points of oscillation, with the lowest point being 0.091 m below the initial release position.

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  • Understanding of harmonic motion principles
  • Familiarity with spring-mass system dynamics
  • Knowledge of oscillation frequency calculations
  • Proficiency in using trigonometric functions in physics
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  • Study the derivation of angular frequency in spring-mass systems
  • Learn about energy conservation in oscillatory motion
  • Explore the effects of damping on oscillation frequency
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fernancb
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Homework Statement


A spring is suspended from a ceiling and has a block attached to its lower end. The block is held a distance y1 from the ceiling (at this point the spring is at its rest length) and released. The block oscillates up and down with its lowest point being 0.091 m below y1. Find the frequency of the motion.


Homework Equations


a(max) = -w^2 *A
y(t) = A cos (wt + phi)

The Attempt at a Solution


a(max) = -w^2*A = -9.8
w^2 = 108
f = 1.65 /s


Someone please help
 
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The block oscillates between the highest and lowest points but the amplitude is half of the distance between them.

ehild
 

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