Calculating Frequency of Vibration for 0.3kg Mass Suspended from 200Nm Spring

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SUMMARY

The frequency of vibration for a 0.3kg mass suspended from a 200Nm spring is calculated to be 4.11Hz. The angular frequency (ω) is determined using the formula ω = √(k/m), where k is the spring constant and m is the mass. Substituting the values, ω equals 25.82 rads-1. The frequency (f) is then derived from ω using the equation f = ω / 2π.

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Homework Statement


A mass of 0.3kg is suspended from a spring 200Nm. If the mass is displaced by 10mm from its equilibrium position and released, for the resulting vibration, calculate:

a. the frequency of vibration.


Homework Equations


ω = √ k/m
f = ω/2∏

The Attempt at a Solution


ω=√ 200/0.3 = 25.82 rads-1

so f = ω / 2∏

f = 25.82/2∏ = 4.11Hz

Does this seem to be correct? Any help would be appreciated.
 
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