Calculating Gauge Pressure and Water Flow in a Multi-Floor House

[qwert13]

Homework Statement

The main water line enters a house on the first floor. The line has a gauge pressure of 1.90 multiplied by 105 Pa.
(a) A faucet on the second floor, 6.3 m above the first floor, is turned off. What is the gauge pressure at this faucet?
(b) How high could a faucet be before no water would flow from it, even if the faucet were open?

Homework Equations

P=F/A
density= m/v
Fbuoyancy= (density)Vg
P + (1/2)(density)(v)^2 + (density)gh = constant
P= (density)gh

The Attempt at a Solution

P= 1000(9.8)(6.3) = 61740? not right. I'm not sure what else to do.

 

[qwert13]

Anyone? It's due tonight so if someone could give me a couple of tips that would be great. thanks in advance

 

[ideasrule]

1. (a) It's 61740 Pa below the gauge pressure on the lower floor, since the pressure applied by the 6.3 m water column is part of the water pressure felt on the first floor. Are you sure the line's gauge pressure is 1.90*105 Pa and not 1.90*105 kPa?

(b) What's the minimum water pressure necessary to force water out?

 

[qwert13]

Yeah actually the pressure is 1.9 x10^5 Pa not 1.9 x 105 Pa. I accidentally typed it wrong onto the computer

 

[qwert13]

ok I figured it out. Thank you so much ideasrule for your help.