Bernoulli? Difference in water pressure between floors

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Homework Help Overview

The problem involves calculating the difference in water pressure between two points in a plumbing system, specifically between a main water line below ground and a faucet located on the second floor of a house. The scenario includes varying pipe diameters and water velocities, and it references Bernoulli's principle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Bernoulli's equation to find the pressure difference, questioning the correct elevation values to use in the calculations. There is also a focus on the implications of pressure being higher in the main line versus the second floor.

Discussion Status

The discussion has evolved with some participants affirming the original poster's calculations while others express confusion regarding the correctness of the answer as marked by an online system. There is a mention of checking with a professor for clarification, indicating ongoing exploration of the problem.

Contextual Notes

Participants note discrepancies between calculated results and feedback from an online submission system, suggesting potential issues with the system's evaluation of the answer.

HeatherP
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Homework Statement



A water line enters a house 2.0 m below the ground. A smaller diameter pipe carries water to a faucet 5.0 m above the ground, on the second floor. Water flows at 2.0 m/s in the main line and at 7.0 m/s on the second floor. Take the density of water to be 1.0 x 103 kg/m3. The difference in pressure between the main line and the second floor is:

A. 7.15 x 104 Pa with the main line at the higher pressure
B. 2.65 x 104 Pa with the main line at the higher pressure
C. 7.15 x 104 Pa with the main line at the lower pressure
D. 2.65 x 104 Pa with the main line at the lower pressure
E. 9.4 x 104 Pa with the main line at the higher pressure


Homework Equations



p + 1/2ρv2 + ρgy

The Attempt at a Solution



main line = second floor

p1 + 1/2ρv21 + ρgy1 = p2 + 1/2ρv22 + ρgy2

p1 + (.5)(1000)(4) + (1000)(9.8)(0) = p2 + (.5)(1000)(49) + (1000)(9.8)(7)

p1 + 2000 + 0 = p2 + 24500 + 68600

p1 - p2 = 24500 + 68600 - 2000

= 9.11 X 104

I was told this answer was incorrect. I think I'm doing something wrong with my y (elevation). I've tried using 0 and 7 and -2 and 5 without success.

Per a search on the internet, it looks like 7.15 x 104 with the main line at the higher pressure is the right answer, but I can not find an explanation why.

Any idea where I'm going wrong?

Thanks!
 
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I think your answer is correct. The main pressure is definitely higher or you couldn't move the water to the upstairs. I don't see any math or conversion errors.
 
p1 + (.5)(1000)(4) + (1000)(9.8)(0) = p2 + (.5)(1000)(49) + (1000)(9.8)(7)

What answer do you get when you use 5m as the change in elevation, rather than 7m?
A. 7.15 x 104 Pa with the main line at the higher pressure
But 5m is the elevation change between the ground and the second floor.

Your question asks for pressure difference between main line and the second floor, which is what you calculated using 7m. Your answer seems correct.
 
Who says the answer is wrong, H?
 
GeorginaS said:
Who says the answer is wrong, H?

It was a question that I had to answer in an online format so it told me that the answer was incorrect once I submitted it.

I’m going to check with my professor today to see why the answer was marked incorrect. I’ll let y’all know what I learn.
 
Well, turns out my answer was right and the computer was wrong. Who would have thought! :)

Thanks all!
 
Wow, how cool is that? See? I didn't steer you wrong for physics advice. :smile:
 

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