Calculating Heart Rate from CRT Display for Beginners

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SUMMARY

The discussion centers on calculating heart rate from a CRT display using a time base of 0.40s/ms and a distance of 1.25cm between peaks. The correct interpretation of the time base is crucial; it should be understood as 0.4s/cm rather than 0.40s/ms. By measuring the distance on the screen and knowing the speed of the trace, one can determine the time for one heartbeat, which translates to a heart rate of 120 beats per minute for a 0.5-second peak-to-peak interval.

PREREQUISITES
  • Understanding of CRT display operation
  • Knowledge of time base measurement in oscilloscopes
  • Familiarity with heart rate calculation methods
  • Basic principles of signal measurement
NEXT STEPS
  • Research the operation of oscilloscopes and their time/div settings
  • Learn about heart rate monitoring techniques and calculations
  • Explore the physics of CRT displays and their applications
  • Study the relationship between distance on a display and time intervals
USEFUL FOR

This discussion is beneficial for students in biomedical engineering, electronics enthusiasts, and anyone interested in understanding heart rate monitoring technology and CRT display calculations.

QueryQueen86
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This question is on the operation of a CRT.

In a heart rate monitor, the time base is a standard 0.40s/ms.
The distance between adjacent peaks on the display is 1.25cm per heart beat.
Calculate the time taken for one heart beat.

Any help with this will be very much appreciated. I missed a few lectures due to illness and now I'm so behind. I don't even know where to start with this!
 
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Welcome to PF.

I don't think I exactly understand your problem statement, because typically your oscilloscope will be given as time/div.

Now if you had said .40s/div then that would indicate to me that you have a .5sec peak to peak, for 1 heart beat, or 60/.5 = 120 beats per minute.
 
QueryQueen86 said:
In a heart rate monitor, the time base is a standard 0.40s/ms.
You have copied this down wrong. The timebase must be time/distance, ie 0.4s/cm

Then if you measure the distance on the screen (1.25cm) and you know how fast the trace is moving you can work out how many seconds the 1.25cm represents.
 

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