Calculating Heat Absorption: Liquid Water at 100°C on a Human Hand

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SUMMARY

The discussion focuses on calculating the heat absorbed by a person's hand when 100 grams of liquid water at 100°C is poured onto it, with the final temperature of the water reaching 37°C. The key concept is the energy released by water as it cools from 100°C to 37°C, which can be quantified using the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C, leading to a total heat absorption of 1,253 Joules for the given scenario.

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  • Understanding of specific heat capacity
  • Basic knowledge of thermal energy transfer
  • Familiarity with the formula Q = mcΔT
  • Concept of temperature change in calorimetry
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Homework Statement



How much heat is absorbed by a person’s hand if 100 grams of liquid water at 100°C is poured on his hand? (Assume the final temperature of the water will be normal body temperature of 37°C)


Homework Equations


dont have any


The Attempt at a Solution


dont have one.
 
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The water changes temperature. So maybe a better question to ask is how much energy is released by 100 g of water when it changes from 100o to 37o C? :wink:
 
i just copied and pasted this question from my homework. i didnt word it
 
ozziegolf05 said:
i just copied and pasted this question from my homework. i didnt word it

Okay. :cool:

Then how much energy is released from 1 gram of water when it changes 1o C?
 

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