How Much Steam Is Needed to Heat Water from 24°C to 90°C?

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SUMMARY

The discussion focuses on calculating the mass of steam required to heat 100 grams of water from 24°C to 90°C. The latent heat of vaporization of steam is established as 540 Cal/g. The total heat released by the steam as it condenses and the subsequent cooling of the condensed water is calculated to be 550m. By equating this to the heat required to raise the temperature of the water, the solution concludes that the mass of steam needed is 12 grams.

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Jahnavi
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Homework Statement



The temperature of 100 gm of water is to be raised from 24°C to 90°C by adding steam to it .Calculate the mass of the steam required for this purpose .

Homework Equations



Latent heat of vaporisation of steam = 540 Cal/g

The Attempt at a Solution


[/B]
Let 'm' be the mass of steam added.

Heat released by steam as it condenses into
water = 540m

Heat released by condensed water as it moves
from 100°C to 90°C = mx1x10 = 10m

Total heat released = 540m+10m= 550m

Heat required by 100gm water to raise its temp from
24°C to 90°C = 100x1x66

Equating the two , 550m = 6600

m = 12gm

Is it correct ?

 
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Jahnavi said:

Homework Statement



The temperature of 100 gm of water is to be raised from 24°C to 90°C by adding steam to it .Calculate the mass of the steam required for this purpose .

Homework Equations



Latent heat of vaporisation of steam = 540 Cal/g

The Attempt at a Solution


[/B]
Let 'm' be the mass of steam added.

Heat released by steam as it condenses into
water = 540m

Heat released by condensed water as it moves
from 100°C to 90°C = mx1x10 = 10m

Total heat released = 540m+10m= 550m

Heat required by 100gm water to raise its temp from
24°C to 90°C = 100x1x66

Equating the two , 550m = 6600

m = 12gm

Is it correct ?
Looks good.
 
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