Calculating Heat of Reaction for H2SO4 and NaOH Solution

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Discussion Overview

The discussion revolves around calculating the heat of reaction for the neutralization of sulfuric acid (H2SO4) with sodium hydroxide (NaOH) in a laboratory setting. Participants explore the methodology for determining the heat change associated with this reaction, including considerations of density and specific heat capacity.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a calculation for the heat of reaction, assuming NaOH is the limiting reactant and using a specific heat capacity of 4.184 J/g°C.
  • Another participant questions the assumption of using 1 g/mL for the density of NaOH, suggesting it should be around 2.130 g/mL instead, but expresses uncertainty about the exact value.
  • There is a discussion about the appropriateness of using 4.184 J/g°C for the specific heat, with some participants agreeing it is acceptable for dilute solutions.
  • A participant mentions conducting a lab on acid-base and metal reactions, seeking to understand differences in energy changes and reaction rates, but does not provide specific details about their calculations or findings.
  • A later reply advises the participant to start a new thread for their unrelated question and emphasizes the need for more information to assist effectively.

Areas of Agreement / Disagreement

Participants express differing views on the density of NaOH and its implications for the calculations. There is no consensus on the correct density value to use, and the discussion remains unresolved regarding the implications of this uncertainty on the heat of reaction calculation.

Contextual Notes

Participants highlight potential limitations in the assumptions made regarding the density of NaOH and the specific heat capacity used in the calculations. The discussion does not resolve these uncertainties.

Who May Find This Useful

This discussion may be useful for students and educators involved in chemistry or related fields, particularly those interested in calorimetry and reaction energetics.

nerdmon
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Homework Statement


When 50.0 mL of 1.0 M H2SO4 at 26.1 celsius was added to 50.0 mL of .976 M NaOH also at 26.1 celsius, the temperature rose to 32.6 celsius. Calculate the heat of reaction.

Homework Equations



H2SO4 (aq) + 2NaOH(aq) --> Na2SO4 (aq) + 2H2O(l)

The Attempt at a Solution


First, I converted both given amount of solutions into moles and found that NaOH was the limiting reactant (made .0488 mol h20 while the sulfuric acid made .1 mol). Then I converted the 50 mL of NaOH into grams (1 g/mL) and plugged that into the q=mcDeltaT equation. I did:
50g*4.184J/gcelcius*6.5 celsius = 1359.8 J
Then I divided that by the mols of NaOH
1359.8 J/.0488 mol = 27864.7541 J/mol

Can anyone confirm if I did this correctly?
 
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1 g/mL is the density of water, therefore I don't think that you can convert 50 mL of NaOH into 50g of NaOH using it. The density of NaOH should be something like 2.130 g/mL, but I'm not sure if that is the correct value or not.
 
oh i assumed 4.184 because it is a dilute solution
 
I think 4.184 is fine for the spec heat. I'm talking about the density of the material that reacted. But maybe I am misunderstanding.
 
ohh good point.. hmm maybe I don't know... thanks for the heads up on that
 
so I am doing a lab on acid and bases and acid and metal reactions, and i have to calculate the energy change, heat

-what would be a difference in the reactions with the heat??
- which one would be faster??
 
ditto_299, you should start a new thread and follow the template. We need more information about your problem (and you should show us what you've tried to do so far) before we can help you. Cheers.
 

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