Calculating Heat of Reaction: NaOH + HCl

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The discussion focuses on calculating the heat of reaction for the neutralization of sodium hydroxide (NaOH) with hydrochloric acid (HCl). The correct balanced equation for the reaction is Na(+) + OH(-) + H(+) + Cl(-) → H2O + Na(+) + Cl(-). To determine the heat produced, participants recommend using the enthalpy of formation values for the reactants and products, applying the formula: summation of products' enthalpies minus summation of reactants' enthalpies. The third equation presented was incorrectly formulated and has been corrected for clarity.

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I have trying to write a hypothesis for this reaction but boy am I lost

NaOH --> Na(+) + OH(-)
NaOH + H (+) + Cl (-) --> H20 + Na(+) + Cl(-)
NaOH +OH (-) + H(+) Cl (-) --> H20 + Na(+) + Cl(-)

Which reaction would produce the most heat and why??
How would i calculate this

Thanks
 
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Look up enthalpies of formations then compare- summation of the products minus the summation of the reactants. By the way, equation #3 makes no sense.
 
Last edited:
whoops Equation #3 shouls read
Na (+) + OH(-) + H (+) + Cl (-) --> H2O + Na (+) + Cl (-)
 

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