Calculating Heat Required to Raise Water Temperature to 100°C

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SUMMARY

The discussion centers on calculating the heat required to raise the temperature of 10.0 kg of water from 20.0°C to 100°C using the formula ΔQ = mass × specific heat × ΔT. The user correctly identifies the temperature change as 80°C but is unsure how to proceed due to a lack of knowledge regarding the specific heat of water. The specific heat of water is established as 4.186 J/g°C, which is essential for completing the calculation.

PREREQUISITES
  • Understanding of the formula for heat transfer: ΔQ = mass × specific heat × ΔT
  • Knowledge of specific heat capacity, particularly for water
  • Basic arithmetic skills for temperature and mass calculations
  • Familiarity with units of measurement (Joules, kilograms, degrees Celsius)
NEXT STEPS
  • Research the specific heat of water and its implications in thermal calculations
  • Practice problems involving heat transfer calculations using different substances
  • Explore the concept of thermal energy and its applications in real-world scenarios
  • Learn about calorimetry and its role in measuring heat changes in chemical reactions
USEFUL FOR

Students studying physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding heat transfer calculations in practical applications.

rijo664
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The question states.

Peter is heating water on the stove to boil eggs for a picnic. How much heat is required to raise the temperature of his 10.0 kg vat of water from 20.0 degrees celsius too 100 degree celsius.

I worked out my problem in this format

Delta Q= mass times specific heat times that change in temperature.

first i subtracted 100 degree celsius with 20.0 degree celsius and i got 80. idk were to go from here. i am stuck. because i don't have specific heat what am i suppose to do. how am i suppose to know how much heat is requred.
 
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rijo664 said:
The question states.

Peter is heating water on the stove to boil eggs for a picnic. How much heat is required to raise the temperature of his 10.0 kg vat of water from 20.0 degrees celsius too 100 degree celsius.

I worked out my problem in this format

Delta Q= mass times specific heat times that change in temperature.

first i subtracted 100 degree celsius with 20.0 degree celsius and i got 80. idk were to go from here. i am stuck. because i don't have specific heat what am i suppose to do. how am i suppose to know how much heat is requred.

Look up the specific heat of water.
 

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