Calculating Height of a Pebbled Launched by a Catapult

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SUMMARY

The problem involves calculating the height a 57 g pebble reaches when launched by a catapult with a spring constant of 310 N/m, initially stretched by 0.30 m. The solution can be approached using either the force of the spring to determine acceleration or the principle of conservation of energy. Ignoring air resistance simplifies the calculations, allowing for a straightforward application of physics equations related to potential and kinetic energy.

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  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of Newton's laws of motion
  • Familiarity with the conservation of energy principle
  • Ability to perform calculations involving mass, force, and acceleration
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  • Learn about the conservation of mechanical energy in physics
  • Explore the equations of motion under constant acceleration
  • Practice problems involving projectile motion and energy transformations
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of projectile motion and energy conservation principles in real-world applications.

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Homework Statement


You shoot a 57 g pebble straight up with a catapult whose spring constant is 310 N/m. The catapult is initially stretched by 0.30 m. How high above the starting point does the pebble fly? Ignore air resistance.
_____ m




Homework Equations



?

The Attempt at a Solution



I am totally lost...this incorporates gravity and the spring...and ah...my head hurts...any one help?
 
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There's more than one way to solve this problem. Do you want to use the force of the spring to figure out its acceleration?

Or to use conservation of energy?

Can you think of any equations that might help you?
 

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