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## Homework Statement

A 48 gram dart is shot vertically upwards from a catapult with a spring constant of 350 N/m. The catapult is initially stretched from the equilibrium point by 21 cm. What is the height above the starting point reached by the dart?

## Homework Equations

KE=PE, rearranging to find h gets h= v^2/2g

find the velocity as it leaves the catapult as v= d(sqrt(k/m))

## The Attempt at a Solution

v= 0.21m (sqrt(350Nm/0.048kg))

= 17.93 m/s

h= (17.93m/s)^2 / 2(9.81m/s^2)

= 16.38 m

does this seem right?