A 48 gram dart is shot vertically upwards from a catapult with a spring constant of 350 N/m. The catapult is initially stretched from the equilibrium point by 21 cm. What is the height above the starting point reached by the dart?
KE=PE, rearranging to find h gets h= v^2/2g
find the velocity as it leaves the catapult as v= d(sqrt(k/m))
The Attempt at a Solution
v= 0.21m (sqrt(350Nm/0.048kg))
= 17.93 m/s
h= (17.93m/s)^2 / 2(9.81m/s^2)
= 16.38 m
does this seem right?