Calculating Height of Lift in Free Fall with Thrown Object

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Homework Help Overview

The problem involves a lift in free fall with a passenger who throws a calculator upwards. The objective is to calculate the height of the lift based on the motion of the calculator and the lift's conditions during free fall.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of free fall on the weight of objects and the motion of the calculator relative to the lift. There is an exploration of how the speed of the lift affects the calculator's trajectory and the assumptions about acceleration due to gravity.

Discussion Status

Some participants have provided interpretations of the problem, noting the effects of free fall on the motion of the calculator. There is an ongoing examination of the assumptions regarding the relationship between the lift and the calculator's movements.

Contextual Notes

Participants are considering the effects of free fall on both the lift and the calculator, questioning how these conditions influence the calculations needed to determine the height of the lift.

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Homework Statement



A lift in free fall with Dr. Bhargav inside. In order to save his calculator he throws it up with 1 m/s from 1 meter above the floor of the lift. It reaches the sealing in two seconds. Calculate height of lift.



The Attempt at a Solution



As the wt in free fall=0.
Then distance traveled in 2 sec=2m
Total height =2+1=3m
:-p
 
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That would be my answer as well. Condolences to the Bhargav family.
 
The speed of the lift (and the passanger) changes as it falls downwards. This means that the speed of the calculator with respect to the lift will increase as time progresses.
 
andrevdh said:
The speed of the lift (and the passanger) changes as it falls downwards. This means that the speed of the calculator with respect to the lift will increase as time progresses.
Not with respect to the lift. Both lift and calculator are accelerating downward at the same rate. As long as you work withing the lift, you can ignore the acceleration due to gravity. That was ritwik06's point when he said "As the wt in free fall=0".
 
Well, for a while there I thought that the calculator stopped falling when it is throwed upwards (blame it on too much leave)!
 

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