Calculating Impulse and Mass of a Basketball

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SUMMARY

The impulse on the basketball, calculated using the formula impulse = F delta t, results in 1 N·s when a force of 10 N is applied over 0.1 seconds. To determine the mass of the basketball, the impulse is equated to delta p, which is m delta v. Given that the ball is dropped from a height of 2 meters, the velocity just before impact can be calculated using the equation v = √(2gh), where g is the acceleration due to gravity (9.81 m/s²). This results in a velocity of approximately 6.26 m/s, allowing for the calculation of mass as m = impulse / delta v, yielding a mass of approximately 0.16 kg.

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Homework Statement


A playerbounces a basketball on the ground. If the ground exerts a force F = 10N on the ball in 0.1 seconds, what is the impulse on the basketball. If the ball is simply dropped from a height of 2m, assuming the impulse to be the same as before, what is the basketball's mass?


Homework Equations



impulse= delta p = m delta v = F delta t

The Attempt at a Solution


For the impulse I have 10N x 0.1 seconds which = 1 N s

For the mass of the basketball I tried m = delta p/delta v

So delta p is the impulse 1 N x s but I don't know how to find delta v
 
Last edited:
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The ball is dropped from a height of 2 m. Can you find v just before it impacts the floor?

It sounds like we should assume the collision is elastic, i.e. the speed of the ball leaving the floor is the same as the speed just before impact.
 

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