Calculating Initial Momentum and Speed of Colliding Railroad Cars

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Homework Help Overview

The discussion revolves around calculating initial momentum and speed in collision scenarios involving railroad cars and recoil in firearms. The original poster presents problems related to momentum conservation and elastic potential energy in springs.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore calculations of initial momentum and speed for colliding railroad cars, as well as recoil velocity for a rifle firing a bullet. There are attempts to confirm calculations and clarify misunderstandings regarding momentum conservation.

Discussion Status

Some participants provide feedback on calculations, with a mix of confirmations and corrections. There is an ongoing exploration of the recoil velocity concept, with participants discussing the relationship between momentum and velocity.

Contextual Notes

Participants are working within the constraints of homework assignments, which may limit the information available for problem-solving. There are indications of potential misunderstandings regarding the application of momentum principles.

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Homework Statement



A railroad car of mass 12,000 kg collides and couples with a second car of mass 18,000 kg that is initially at rest. After the collision, both move at a speed of 4.8 m/s.

What is the initial momentum and initial speed of the first car?


Homework Equations



The formulas that I´ve used are:

Pi = pf = mv
vi = pf/m

The Attempt at a Solution



So, I´d like someone to confirm my answers:

For Pi (initial momentum) I did:

Pi = pf = mv = (12,000kg + 18,000kg)(4.8m/s) = 144,000kg.m/s

For Vi (initial speed) = Pf/m = 144,000/12,000 = 12m/s.

Are my answers correct?
 
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They appear to be correct. Nice job.
 
Thankss! =D
 
I have another question. Could you confirm the other as well? Please??

1. Homework Statement

A rifle with a mass 2.2kg fires a bullet with a mass of 5g. The bullet moves with a velocity of 600m/s.

1) What is the momentum of the bullet after it´s fired?
2) What is the recoil velocity of the rifle assuming that no external forces act on the rifle?2. Homework Equations

P = mv

3. The Attempt at a Solution

For question 1) P = 0.005kg x 600m/s = 3kg. m/s.

For question 2) I wrote 0.

Are my answers correct?
 
1) Should be 30 kgm/s, not sure if you just had a typo.
2) 0 is incorrect. You have the 30 kgm/s of momentum from the bullet, right? Therefore, there must be an equal and opposite momentum acting on the rifle.
 
I wish it were at typo. Actually, the calculation is correct. Am I using the wrong information?

Now for question number 2, you mean p = -p, so the answer would be -30?
 
I just would like to say that I am truly appreciating your help! :)
 
Whoops, my bad on number 1. MY typo on the calculator xD. As for 2), yes, the momentum of the rifle would be -3, but you're looking for the velocity.
 
help me with this 1 please
A teddy bear of mass 400 grams is hung from the end of a spring. The spring measures 51.0cm long in the rest position; when the teddy bear is attached to the end of the spring, the spring extends to 72.0cm. Calculate the elastic potential energy stored in the spring when extended to 72.0cm.
 
  • #10
hahaha no problem :) You are still being EXTREMELY helpful.

The question: A rifle with a mass 2.2kg fires a bullet with a mass of 5g. The bullet moves with a velocity of 600m/s.

I am looking for recoil velocity,

would that be 2.2 divided by 600m/s ?
 
  • #11
I am sorry but I am not sure about I should find the recoil velocity.
 
  • #12
No, your momentum is -3, right? P=mv. Mass of the rifle is 2.2kg. What is your velocity?

As for Tom, you should probably post your problem in your own thread. You also need to post an attempt at a solution first.
 
  • #13
v = p/m
v = -3kg.m/s divided by 2.2kg = -1.36 m/s.

So to find recoil velocity I should just use v=p/m. That´s how I find it, right?
 
Last edited:
  • #14
Divide, not multiply ;)

Edit: Yes, that's correct :)
 
Last edited:
  • #15
Thank you so much (again!) xD
 
Last edited:
  • #16
You did most of the work yourself ;), nice work. Now I'm off to bed :zzz:
 
  • #17
have a good night! :)
 

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