Calculating Initial Velocity & Angle of a Moving Ball

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The discussion focuses on calculating the initial velocity and angle of a moving ball using its horizontal and vertical position functions: x(t) = 84 cm + 27 cm/s * t and y(t) = 88 cm + 46 cm/s * t - 490 cm/s² * t². To find the magnitude of the initial velocity, participants suggest differentiating the position functions to obtain the horizontal (vx) and vertical (vy) components of velocity. By evaluating these components at time t = 0, the initial velocity (vo) can be calculated using the formula vo = sqrt(vx² + vy²).

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A ball is moving through the air as shown. Its horizontal position x and vertical position y can be described by two functions: x(t) = a + b*t and y(t) = c + d*t + e*t*t.
Here t represents time and

a= 84 cm, b=27 cm/s, c=88 cm, d=46 cm/s and e=-490 cm/s/s.

What is the magnitude of the initial velocity of the ball? and what is the angle between the initial velocity and the horizontal?

Could anyone provide a much needed hint to get going on this problem?
 
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Find dx/dt and dy/dt. That will give you vx and vy. Put t = 0 to get vo = sqrt(vx^2 + vy^2)
 
ok i got it thanks so much!
 

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