Calculating Inverse Functions for Cubic Equations for TI-83 Users

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Calculating the inverse of the cubic function x^3 + 4x + 1 requires using the cubic formula, which is complex and not typically expected in classroom settings. Users are encouraged to find alternative methods to solve related problems without explicitly computing the inverse. The discussion highlights the challenges of using the TI-83 graphing calculator for this purpose. Clarification on the specific problem text is sought to provide more targeted assistance. Overall, the focus is on understanding the limitations of calculating inverses for cubic equations.
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Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1. And if possible how you would calulate that on the TI-83 graphing calculator. Thanks
 
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Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1.

You don't.

The exact formula for the inverse of this function requries the cubic formula, which is fairly complicated (although in this case the result is readable), and is almost certainly not what you are expected to do in class; there's probably a way to find the answer to your problem without having to explicitly compute this inverse.
 
It is expected. If you know how to solve this equation please tell me.
 
I see you've found the cubic formula. :smile: Do you still need help with it?

I'm curious what the actual text of the problem is.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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