Calculating Inverse Functions for Cubic Equations for TI-83 Users

Click For Summary
SUMMARY

The discussion focuses on calculating the inverse function of the cubic equation x^3 + 4x + 1 using a TI-83 graphing calculator. The consensus is that directly computing the inverse requires the cubic formula, which is complex and not typically expected in classroom settings. Participants suggest that there are alternative methods to approach the problem without explicitly finding the inverse. The need for clarity on the original problem statement is also highlighted.

PREREQUISITES
  • Understanding of cubic equations and their properties
  • Familiarity with the cubic formula for finding roots
  • Basic operation of the TI-83 graphing calculator
  • Knowledge of inverse functions and their significance
NEXT STEPS
  • Research the cubic formula and its application in solving cubic equations
  • Explore alternative methods for finding inverse functions without explicit calculation
  • Learn how to use the TI-83 to graph functions and analyze their inverses visually
  • Study the implications of inverse functions in algebra and calculus
USEFUL FOR

Students studying algebra, educators teaching cubic equations, and anyone using the TI-83 calculator for advanced mathematical functions.

ATCG
Messages
17
Reaction score
0
Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1. And if possible how you would calulate that on the TI-83 graphing calculator. Thanks
 
Mathematics news on Phys.org
Could somebody please explain to me how you would calulate the inverse functions of x^3+4x+1.

You don't.

The exact formula for the inverse of this function requries the cubic formula, which is fairly complicated (although in this case the result is readable), and is almost certainly not what you are expected to do in class; there's probably a way to find the answer to your problem without having to explicitly compute this inverse.
 
It is expected. If you know how to solve this equation please tell me.
 
I see you've found the cubic formula. :smile: Do you still need help with it?

I'm curious what the actual text of the problem is.
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 10 ·
Replies
10
Views
13K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K