Calculating Launch Velocity for a Motorbike Jump

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SUMMARY

To calculate the launch velocity required for a motorbike to clear a 40m gap while landing 15m below the ramp's tip, one must apply principles of projectile motion. The ramp is inclined at an angle of 53 degrees. Using the equations of motion, specifically the kinematic equations, one can derive the necessary initial velocity. The key factors include the horizontal distance, vertical drop, and launch angle.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic trigonometry for angle calculations
  • Ability to draw and interpret motion diagrams
NEXT STEPS
  • Study the kinematic equations for projectile motion
  • Learn how to resolve vectors into horizontal and vertical components
  • Explore the impact of launch angles on projectile trajectories
  • Practice solving similar physics problems involving angles and distances
USEFUL FOR

This discussion is beneficial for physics students, motorcycle stunt coordinators, and anyone interested in understanding the mechanics of jumps and projectile motion in sports.

QuantumKing
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some guy on a moterbike rides up a ramp to clear a gap of 40m, where the flat landing is, situated 15m below the horizontal line of the tip of the ramp. The ramp is at an angle of 53degrees above the horizontal. what velocity must the rider lift off the ramp with?

I serioulsy have no ideas on where to start with this, I've tried several different scribbles and got nowhere. Some help would be appreciated! thanks
 
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Start by drawing a picture and then write down what you know (given from problem) and then write down what you need to know. Hopefully this will get you started in the right direction.
 
I have a picture, and i know the info. but it seems to me like there isn't enough info, i can't work with it.
 

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