Launch Velocity for Satellite from Mt. Everest to Orbit Earth

[cubejunkies]

At what horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around the earth?

The book earlier in the chapter provides two things relating to Mt. Everest:
1. g at the top of Mt. Everest is 9.77 m/s²
2. The top of Mt. Everest according to the book is 8850 m

Unfortunately, I honestly have no idea how to begin to do this problem, and all of my buddies in physics are as perplexed as I am.

Thank you to anyone who helps!
Anthony

 

[The legend]

The circular orbital velocity of a satellite is?
If you know that, the answer is just of substitute and solve.

 

[cubejunkies]

I don't understand what you mean... :/

 

[The legend]

just that, do you know the formula for orbital velocity of a satellite?

 

[cubejunkies]

I don't, I don't believe our teacher ever went over anything like that and our book is super vague. What is the orbital velocity of a satellite equation?

 

[skeptic2]

Do you know why a satellite stays in orbit? It is in equilibrium between two forces. If you know what those two forces are then you need to know how to calculate their strength in order for them to be in equilibrium?

 

[cubejunkies]

Well there's the force of gravity pulling inwards, but there's no such thingas centrifugation in terms of force so I have no idea

 

[The legend]

I don't, I don't believe our teacher ever went over anything like that and our book is super vague. What is the orbital velocity of a satellite equation?

I won't tell you that, but you know that there's a centripetal force acting on the satellite caused by gravitation.
What is the magnitude of centripetal force in terms of m,v,r(r being Radius of earth+Height)? and magnitude of gravitational force according to Newton's law of gravitation?

Equate them ...
jumble with the equation until you get v that is the orbital velocity.