Calculating Magnetic Field in a Straight Wire of Radius R with Current I

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SUMMARY

The discussion focuses on calculating the magnetic field inside a straight wire of radius R carrying a uniformly distributed current I. The key equations derived include B*2πr = μi_inside and i_inside = I*(πr²)/(πR²), leading to the conclusion that i_inside = I*r²/R². This relationship is established through the ratio of the areas of the cross-section of the wire, confirming that the current density is uniform across the wire's cross-section.

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Question:
-straight wire with radius R, carrying current I
-current is uniformly distributed across the cross sectional area of wire
-calculate the magnetic field inside wire as function of distance r from the center of the wire

In the solution, there is a picture of the cross section of the wire, and the current is going into the page, ie X.
there is an imaginary circle, "amperian loop" with radius r, inside the wire.
then, B*2*pi*r = u*i_inside (equation 1)
then somehow i_inside = I*(pi*r^2)/(pi*R^2) = I*r^2/R^2 (equation 2)
This i don't understand. I know it something to do with the fact that current is uniformly distibuted, but how to get equation 2?
Is it just a ratio?
Thanks!
 
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Question has been solved in other forum.
Sorry, not too sure how to delete this thread...
 
Yes, it's just the ratio of Areas (inside / entire)
 

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