Calculating magnetic force on circular coil carrying current

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Homework Statement


A circular coil with center on the z axis and orthogonal to the xy axis carries a current. The coil is in a magnetic field B with axial symmetry compared to the x axis. B forms an angle θ with the z axis. Calculate the magnetic force acting on the coil.

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2. Homework Equations

$$\vec{F_B} = i \vec{dl} x \vec{B}$$

The Attempt at a Solution


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I tried considering $$ dl = r d\phi $$
So [itex]F = irB_zd\phi[/itex]
where Bz is [itex]Bcos\theta[/itex]

By is null because it has opposite verse on opposite points of the coil. So I can consider just Bz

$$ F = irBcos\theta d\phi = irBcos\theta \int_0^{2\pi} d\phi = 2\pi irBcos\theta$$

The result, according to the book, is [itex]2\pi irBsin\theta[/itex]
Why?
 
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How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?
 
Vagn said:
How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?

It is the angle between B and Bz!
 
rude man said:
What does this mean?

I can't understand what does it mean, actually.