Calculating magnetic force on circular coil carrying current

AI Thread Summary
A circular coil carrying current is placed in a magnetic field with axial symmetry, forming an angle θ with the z-axis. The magnetic force on the coil is calculated using the equation F_B = i dl x B, leading to an initial result of 2π irBcos(θ). However, the book states the correct answer is 2π irBsin(θ), prompting confusion about the definition of θ. Clarification reveals that θ is the angle between the magnetic field B and the z-axis, not the horizontal. The discussion highlights the importance of clear problem statements in physics education.
cseil
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Homework Statement


A circular coil with center on the z axis and orthogonal to the xy axis carries a current. The coil is in a magnetic field B with axial symmetry compared to the x axis. B forms an angle θ with the z axis. Calculate the magnetic force acting on the coil.

exerc.png


2. Homework Equations

$$\vec{F_B} = i \vec{dl} x \vec{B}$$

The Attempt at a Solution


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I tried considering $$ dl = r d\phi $$
So F = irB_zd\phi
where Bz is Bcos\theta

By is null because it has opposite verse on opposite points of the coil. So I can consider just Bz

$$ F = irBcos\theta d\phi = irBcos\theta \int_0^{2\pi} d\phi = 2\pi irBcos\theta$$

The result, according to the book, is 2\pi irBsin\theta
Why?
 
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How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?
 
Vagn said:
How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?

It is the angle between B and Bz!
 
cseil said:
The coil is in a magnetic field B with axial symmetry compared to the x axis.
What does this mean?
 
rude man said:
What does this mean?

I can't understand what does it mean, actually.
 
cseil said:
I can't understand what does it mean, actually.
So ask! The problem is not you, it's the instructor who can't write understandably!
 
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