Calculating magnetic force on circular coil carrying current

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Homework Help Overview

The problem involves calculating the magnetic force acting on a circular coil carrying current in a magnetic field with axial symmetry. The coil is oriented with its center on the z-axis and is perpendicular to the xy-plane, while the magnetic field forms an angle with the z-axis.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the magnetic force using the equation for magnetic force on a current-carrying conductor, considering the contributions from the magnetic field components. Participants question the definition of the angle θ and the implications of axial symmetry in the magnetic field.

Discussion Status

Participants are actively discussing the definitions and implications of the problem setup, particularly regarding the angle θ and the meaning of axial symmetry in the context of the magnetic field. There is a lack of consensus on the interpretation of these concepts, with some seeking clarification on the instructor's wording.

Contextual Notes

There is confusion regarding the definitions provided in the problem statement, particularly concerning the angle θ and the nature of the magnetic field's axial symmetry. Participants express uncertainty about the clarity of the problem description.

cseil
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Homework Statement


A circular coil with center on the z axis and orthogonal to the xy axis carries a current. The coil is in a magnetic field B with axial symmetry compared to the x axis. B forms an angle θ with the z axis. Calculate the magnetic force acting on the coil.

exerc.png


2. Homework Equations

$$\vec{F_B} = i \vec{dl} x \vec{B}$$

The Attempt at a Solution


[/B]
I tried considering $$ dl = r d\phi $$
So F = irB_zd\phi
where Bz is Bcos\theta

By is null because it has opposite verse on opposite points of the coil. So I can consider just Bz

$$ F = irBcos\theta d\phi = irBcos\theta \int_0^{2\pi} d\phi = 2\pi irBcos\theta$$

The result, according to the book, is 2\pi irBsin\theta
Why?
 
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How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?
 
Vagn said:
How does your book define ##\theta##? Is it the angle the magnetic field makes with the horizontal(i.e. ##B_y##)?

It is the angle between B and Bz!
 
cseil said:
The coil is in a magnetic field B with axial symmetry compared to the x axis.
What does this mean?
 
rude man said:
What does this mean?

I can't understand what does it mean, actually.
 
cseil said:
I can't understand what does it mean, actually.
So ask! The problem is not you, it's the instructor who can't write understandably!
 

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