Calculating Mass of Dry Wood in Buoyancy Problem

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SUMMARY

The problem involves calculating the mass of a dry wood raft that supports a pig weighing 1158 kg, with the raft completely submerged in water. Given the raft's volume of 3.40 m³ and the density of water at 1000 kg/m³, the buoyant force must equal the total weight of the pig and the raft. Using the equation for buoyant force, B = pfluid(g)Vobj, the mass of the dry wood can be determined by rearranging the equations to find the density of the wood and subsequently its mass.

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Homework Statement


A pig of mass (1158kg) is placed on a fart made of dry wood. The raft completely submerged in water so that the raft's top surface was just level with the surface of the lake. If the raft's volume was 3.40 m^3, what was the mass of the raft's dry wood? Density of water is 1000 kg/m^3


Homework Equations


m' = (p2 - p1)V
p = density
V = Volume

Buoyant Force
B = pfluid(g)Vobj

Gravity
mg

The Attempt at a Solution


I have no idea where to begin with this. The only density I am given is of water not of the wood.
 
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Buoyant force = weight of pig and raft
 

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