Calculating Maximum Torque on Rotating Square

[physics_10]

A square, 0.69 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 17.1 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?

I have no idea how to approach this problem.

I tried doing Force x max distance from axis
so..
17.1 N x $$\sqrt{}2[/tex(0.69 / 2)<br /> <br /> but i was not getting the correct answer... any ideas?$$

 

[tiny-tim]

hi physics_10!

(have a square-root: √ )

A square, 0.69 m on a side, is mounted so that it can rotate about an axis that passes through the center of the square. This axis is perpendicular to the plane of the square. A force of 17.1 N lies in this plane and is applied to the square. What is the magnitude of the maximum torque (in N*m) such that a force could produce?

I have no idea how to approach this problem.

I tried doing Force x max distance from axis
so..
17.1 N x $$\sqrt{}2[/tex(0.69 / 2)<br /> <br /> but i was not getting the correct answer... any ideas?$$

$$<br /> (ie 17.1 x 0.69/√2 ?)<br /> <br /> looks right to me <img src="https://cdn.jsdelivr.net/joypixels/assets/8.0/png/unicode/64/1f615.png" class="smilie smilie--emoji" loading="lazy" width="64" height="64" alt=":confused:" title="Confused :confused:" data-smilie="5"data-shortname=":confused:" />$$