Calculating Mean Distance Traveled by Pi-Mesons at Speed v=0.3c

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SUMMARY

The discussion focuses on calculating the mean distance traveled by pi-mesons moving at a speed of v=0.3c, given their mean life of 2.6 x 10^-8 seconds. The time dilation formula T = T_0 / √(1 - v²/c²) is critical for this calculation, where T_0 represents the proper time experienced by the pi-meson. Participants emphasize the importance of understanding time dilation in special relativity to solve the problem effectively. An example calculation is suggested to clarify the concept further.

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  • Understanding of special relativity concepts
  • Familiarity with time dilation and proper time
  • Basic knowledge of physics equations related to motion
  • Ability to perform calculations involving square roots and fractions
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  • Learn how to apply the time dilation concept to particle physics problems
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This discussion is beneficial for students preparing for physics examinations, particularly those studying special relativity and particle physics, as well as educators seeking to clarify these concepts for their students.

EIRE2003
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A beam of charged pi-mesons is traveling with a speed of v=0.3c.
The mean life of a pi-meson is 2.6 x 10^-8s. What is the mean distance traveled by a pi meson before it decays?

How do u do this?
 
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Do you understand how to calculate time dilation?

- Warren
 
No :confused:
 
Have you not been paying attention in class or something?

- Warren
 
Im not in school i finished last yr. I am repeating cause our teacher was never into teach us the stuff. So I am trying to learn this stuff myself from the past examination papers. My leaving cert is in june.
 
Well, in special relativity theory, when an object is moving at velocity v with respect to a stationary observer, the object will appear to suffer a time dilation of

T = \frac{T_0}{\sqrt{1 - v^2/c^2}}

where T is the time measured by the observer and T_0 is the time as measured in the rest frame of the pion.

In other words, the pion will seem to live longer when moving than it would when at rest by a factor of 1/\sqrt{1 - v^2/c^2}.

Does this make sense?

- Warren
 
:confused: not really. I've seen this in hawkings book universe in a nutshell but never understood it.

I don't understand what T_o is?

Maybe if u cud actually do the sum and i will go through it and try to get my head around it. Then it won't be as confusing. I just need an example of how its done.
 

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