Calculating Measurement Error for a Digital Lux Meter

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Homework Help Overview

The discussion revolves around calculating measurement error for readings taken with a digital lux meter, specifically focusing on the implications of a stated 5% error tolerance and the device's last digit precision of 0.1 lux.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore whether the 5% error applies independently to each measurement and question the nature of reading errors. There is confusion about how to incorporate the last digit's precision into the overall error calculation.

Discussion Status

Participants are actively questioning the assumptions regarding systematic error and the independence of measurement errors. Some guidance has been offered regarding the interpretation of the 5% error, but clarity on how to apply the reading error remains unresolved.

Contextual Notes

There is mention of the professor's instruction to consider the error as 5% without additional factors, and the condition of the measuring devices is noted as potentially affecting the reliability of readings.

AltruisticVariation
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Homework Statement


For my lab report I am asked to calculate the error of a couple of measurements which I did with a lux meter. I know that the lux meter has tolerance(or accuracy?) 5%. The instrument is digital and it's last digit is 0.1. The maximum reading is 47.5 lux.

Homework Equations

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The Attempt at a Solution

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Is the error 5% of each measurement? Should I add reading error? I'm pretty confused, sorry if it's a silly question.
 
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AltruisticVariation said:
Is the error 5% of each measurement?
Do you mean, are the errors on different readings independent? Hard to know without knowing how the device works and what its chief source of error is, but I would expect some degree of systematic error.
AltruisticVariation said:
Should I add reading error?
How is the reading done? Is it a digital readout or a sweeping hand on a dial?
 
Edited the post. The professor said that the error is 5%, nothing more and now I can't figure it out.
 
AltruisticVariation said:
Edited the post. The professor said that the error is 5%, nothing more and now I can't figure it out.
Then take is as independent on each reading.
Just noticed you did state it is a digital readout. You mention the last digit is 0.1, but that doesn't help without knowing how large a typical reading is.
 
haruspex said:
Then take is as independent on each reading.
Just noticed you did state it is a digital readout. You mention the last digit is 0.1, but that doesn't help without knowing how large a typical reading is.

What do you mean by independent on each reading? 5% of each reading? The minimum value is 0 and the maximum 47.5. So the bigger the reading the bigger the error? For example what is the error when the reading is 0?
 
AltruisticVariation said:
the bigger the reading the bigger the error?
That's what is usually meant by 5%.
AltruisticVariation said:
What do you mean by independent on each reading
Measuring devices tend to have some systematic error. E.g. all readings tend to be, say, 1% over; or all tend to be so much under, etc.
Independent would mean that the error in one reading is unrelated to errors in other readings.
 
haruspex said:
That's what is usually meant by 5%.

Measuring devices tend to have some systematic error. E.g. all readings tend to be, say, 1% over; or all tend to be so much under, etc.
Independent would mean that the error in one reading is unrelated to errors in other readings.
Well yes possibly then we suppose we have no systematic error. Generally the devices were in pretty bad situation so the professor told us to consider the error 5%.
So should I add the reading error (+0.1 to all errors)? That makes sense to me.
 
AltruisticVariation said:
Well yes possibly then we suppose we have no systematic error. Generally the devices were in pretty bad situation so the professor told us to consider the error 5%.
So should I add the reading error (+0.1 to all errors)? That makes sense to me.
It depends. If a reading is 100 then the ±5% is going to make the ±0.05 irrelevant.
 
haruspex said:
It depends. If a reading is 100 then the ±5% is going to make the ±0.05 irrelevant.
Yes sure. So the reading error isn't 0.1 that I thought? :nb)
 

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