MHB Calculating Mine Proposal: Silver, Copper, and Gangue Production and Profits

  • Thread starter Thread starter Scott29
  • Start date Start date
  • Tags Tags
    Calculation
Scott29
Messages
1
Reaction score
0
I'm in year 8 and have a maths question for science. I have been given some information to go off.

We have a task where we have to 'plan' a new mine proposal. I am doing accounting. I need help with 2 questions.

- How much silver, copper, and gangue will be produced
- How much money will we make (silver, copper, and the total)

There is 2.5kg of copper per tonne of ore, and 850,000,000 tonnes or ore. There is also .5g of silver per tonne, and producing 1 tonne of copper will produce 98 tonnes of gangue.

The main thing i am stuck on is the 'per'. Does that mean times or divide. No matter who i ask i keep getting different answers. I thinks its times. Also, i have figured it out about 8 times, and got about 5 different answers because i keep thinking, "maybe this is how your supposed to do it".

To get the prices, it is $4.04 per pound. You will need a pound to kilogram/tonne calculator seeing as i live in a country that doesn't use pounds.

Thanks heaps, I know its a lot but I'm so stuck and this is my one job so i don't want to stuff it up.
 
Mathematics news on Phys.org
Scott29 said:
I'm in year 8 and have a maths question for science. I have been given some information to go off.

We have a task where we have to 'plan' a new mine proposal. I am doing accounting. I need help with 2 questions.

- How much silver, copper, and gangue will be produced
- How much money will we make (silver, copper, and the total)

There is 2.5kg of copper per tonne of ore, and 850,000,000 tonnes or ore. There is also .5g of silver per tonne, and producing 1 tonne of copper will produce 98 tonnes of gangue.

The main thing i am stuck on is the 'per'. Does that mean times or divide. No matter who i ask i keep getting different answers. I thinks its times. Also, i have figured it out about 8 times, and got about 5 different answers because i keep thinking, "maybe this is how your supposed to do it".

To get the prices, it is $4.04 per pound. You will need a pound to kilogram/tonne calculator seeing as i live in a country that doesn't use pounds.

Thanks heaps, I know its a lot but I'm so stuck and this is my one job so i don't want to stuff it up.
Hi Scott29,

"per" means that each tonne of ore produces 2.5kg of copper and 0.5g of silver. To get the total amount of copper (in kg) and silver (in grams), you have to multiply these figures by the number of tonnes of ore.

One pound (lb.) is 0.453592 kg.

Does this answer your question ? Pleas feel free to write back if you need further help.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top