Calculating Molar Mass from Titration Data

[A_Munk3y]

Homework Statement

A 0.149 g sample of a weak acid (HA) requires 16.80 mL of 0.110 M NaOH to completely reach the equivalence point. What is the Molar Mass of the acid?

Homework Equations

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The Attempt at a Solution

i don't think i did it right.
i just did 0.0168Lx0.110M= 0.001848 moles
then did 0.149/0.001848 = 80.69 g/mole

dont think that's right though, because i think I am supposed to use NaOH somehow

 

[Borek]

dont think that's right though, because i think I am supposed to use NaOH somehow

You have used it to calculate number of moles.

I got 80.63 g/mol, your result differs because of rounding errors.

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[A_Munk3y]

oh, so i was right :)
ok thank you sir!