Calculating Moles and Mass: Ca(NO3)2, Ca2+ ions, and NaCl - Homework Solutions

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SUMMARY

The mass of one mole of calcium nitrate, Ca(NO3)2, is calculated to be 164.1 grams. For 0.05 moles of Ca(NO3)2, the number of Ca2+ ions is determined using Avogadro’s number, resulting in 3.011 x 10^22 Ca2+ ions. Additionally, the number of moles of sodium chloride (NaCl) in 450 grams is calculated to be approximately 5.95 moles, based on its molar mass of 75.53 g/mol. The calculations confirm the accuracy of the first and last questions posed in the homework statement.

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  • Understanding of molar mass calculations
  • Familiarity with Avogadro’s number (6.022 x 10^23 1/mol)
  • Basic knowledge of stoichiometry
  • Ability to perform unit conversions in chemistry
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  • Study the concept of molar mass and its calculation for various compounds
  • Learn about stoichiometric relationships in chemical reactions
  • Explore the application of Avogadro’s number in different chemical contexts
  • Investigate the properties and calculations related to ionic compounds like NaCl
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Homework Statement


a) What is the mass of one mole of Ca(NO3)2?
b) How many Ca2+ ions are there in 0.05 moles of Ca(NO3)2?
c) How many moles ofNaCl are there in 450 g of this substance?
(Avogadro’s number is 6.022*1023 1/mol.)


Homework Equations



The Attempt at a Solution


a)
m=n*M=1*164.1
m=164.1g
b)
I have NO IDEA, help me
c)
n=450/75.53
n=5.95mol
 
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You see the mole ratio directly in the molecular formula. Now instead of having 1 mole of Ca(NO3)2, you have only 0.05 moles. So how many of Ca+2?
 
0.05*6.022*E23?
first and last question are true ?
 

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