Calculating Momentum and Impulse of a Golf Ball and Club

[Black_Hole???]

A golfer hits a golf ball of mass 0.045 kg the ball over some short trees. He hits the ball at
an angle of 600 to the horizontal and it travels a horizontal distance (Range) of 60.0 m in a
time of 8.00 s. The golf club of mass 0.60 kg is in contact with the ball for a time of 2.40
ms.

(a) What is the average impulsive force on the golf ball?




ANSWER: ____________ ___

(b) What is the average impulsive force on the golf club?




ANSWER: ____________ ___

(c) What is the change in momentum of the golf club?




ANSWER: Change in Momentum = ___________ ______


Answers are suppose to be A1) 281.25 A2) -281.25 A3) -.675 kgm/s

 

[rl.bhat]

Don,t say bump
Open the book. Find the relevant formula. Show your effort.

 

[Black_Hole???]

refresh. Just putting the forums on my subscription. not trying to get people to do it for me

 

[Black_Hole???]

Ok i know the formula that i need to use but i don't know how to solve for velocity of the ball.

What i would use though if i had the velocity of the ball would be.

Impulse = (p2-p1)/(t2-t1)

P = mv which is finding momentum.

I have an idea in which to find the velocity and that would be a free falling problem. But i can't get anything to work.

If you have any ideas please help.

Thanks

 

[Black_Hole???]

refresh

 

[Black_Hole???]

refresh

 

[Black_Hole???]

Someone please help

 

[rootX]

If it covers 60 m in 8s, what is the horizontal component of velocity?
(horizontal v stays constant for projectiles)
And then, you know the angle which would help you find the y component and you get the initial speed after 2.40 ms contact ...