Calculating Momentum of a Spacecraft with Thruster Firing?

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SUMMARY

The discussion focuses on calculating the initial and final momentum of a spacecraft with a mass of 1.0 x 104 kg traveling at 1200 m/s when a thruster exerts a force of 25 kN for 2.0 minutes in the opposite direction. The key equations used include impulse, defined as J = Δp = pf - pi, and the conversion of time from minutes to seconds, resulting in 120 seconds. The correct application of these principles leads to the determination of the spacecraft's momentum before and after the thruster firing.

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Homework Statement



a 1.0*10^4kg spacecraft is traveling through space with a speed of 1200 m/s realtive to earth. a thruster fires for 2.0 min, exerting a continuous force of 25kN on the spacecraft in a direction opposite the spacecraft s motion . calculate the initial momentum and the fianl momentum kof the spacecraft .



Homework Equations





The Attempt at a Solution

 
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You need to show work here in order to get help. Those are the rules. What have you tried so far? What are you thoughts on the problem?
 
(-25*10^3)(2.0)=(1.0x10^4)(1200)+(1.0*10^4)(mvi)
 
OK. Your big problem is with units. You have seconds on one side of the equation and minutes on the other side of the equation.

Also, remember the equation is:

Impulse =Change in Momentum.
J=\Delta p=p_f-p_i

Check your signs on the RHS of your equation.
 
Last edited:
ok so it would be 120s instead of 2.0min
 
(-25*10^3)(120)= (1.0*10^4)(mvi)-(1.0x10^4)(1200)
 
jamiescience said:
(-25*10^3)(120)= (1.0*10^4)(mvi)-(1.0x10^4)(1200)

That looks good to me.
 

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