Calculating Muonic Atom Energy: Ground State and Excited State Wavelength

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Homework Help Overview

The problem involves calculating the energy levels of a muonic atom formed by a muon captured by a deuteron, specifically focusing on the ground state and the first excited state, as well as determining the wavelength associated with transitions between these states.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate quantum numbers for the ground and excited states, with some suggesting that the ground state corresponds to n=1 and questioning the value of n for the first excited state. There is also uncertainty about how to apply the energy equations correctly in the context of a muonic atom compared to a hydrogen atom.

Discussion Status

The discussion is ongoing, with some participants providing insights into the differences between the muonic atom and hydrogen atom, particularly regarding the reduced mass and the applicability of certain equations. There is a recognition that the ground state is n=1 and that n=2 is likely the first excited state, but further clarification on the energy equations is needed.

Contextual Notes

Participants note that the equations used for hydrogen may not directly apply to the muonic atom due to differences in mass and the need for corrections related to reduced mass. There is also mention of the origin of the constant 13.6 eV and its relevance to the problem.

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Homework Statement


A muon is captured by a deuteron to form a muonic atom. Find the energy of the ground state and the first excited state.
find the wavelength when the transition occurs

Homework Equations


E[tex]_{n}[/tex] = [tex]\frac{-13.6Z^{2}}{n^{2}}[/tex]

[tex]\frac{1}{\lambda}[/tex] = R{[tex]\frac{1}{n_{f}^{2}}[/tex]-[tex]\frac{1}{n_{i}^{2}}[/tex]}

The Attempt at a Solution


I'm not sure what the n's are for each state. I think [tex]n_{f}[/tex] or ground state = 1 but don't know where to go from here
 
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Those equations would be right if you were just talking about the hydrogen atom. All you'd have to do would be to plug the right numbers in. Z=1, n=1 in the ground state... and what number would you give one energy level above the ground state n=1?

Unfortunately, it's slightly more complicated than that. Where does the number 13.6 come from? And how is this system different from a hydrogen atom?
 
the deuteron is the hydrogen atom, it's [tex]^{2}H[/tex] and the 13.6 is [tex]\frac{ke^{2}}{2a_{o}}[/tex].

we're not sure how to utilize the equations though. like what is the first excited state? is ground state n=1? how is [tex]n_{i}[/tex] found? once that is found the wavelength should be easy but we're just not sure how determine the excited state, is it n = 2? tough to tell n could = 2,3,4...[tex]\infty[/tex]
 
Yes, the ground state is n=1 like I said above, and n=2 is the first excited state.
The term you used for the bohr radius is only applicable for the hydrogen atom- a bound state of a proton (or deuteron) and an electron. It's a slight approximation because the reduced mass of the system is very nearly the mass of the electron. This approximation is actually slightly more accurate for a deuteron + electron than for a proton + electron.. But what's the mass of the muon?
Similarly, you can't use the Rydberg formula for anything other than a common or garden hydrogen atom. Find a version of your first equation that includes a correction for the reduced mass of the system, and convert the difference between the two energy levels to a wavelength.
 

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