Calculating Orbital Height for a Satellite Orbiting the Earth

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Homework Help Overview

The discussion revolves around determining the orbital height of an artificial satellite that must remain geostationary relative to the Earth. The problem is situated within the context of planetary motion and Kepler's Laws.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the applicability of Kepler's Laws, particularly questioning the relevance of the second and third laws. There is uncertainty about the necessary period for a geostationary orbit, with some suggesting it must match the Earth's rotation period of 24 hours. Others express confusion regarding the required information, such as the orbital period and the calculations leading to an initial incorrect distance.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on the problem and attempting to clarify their understanding of the relevant laws. Some guidance has been offered regarding the orbital period, but there is no consensus on the correct approach or calculations yet.

Contextual Notes

Participants mention a lack of information, specifically the orbital period, which is crucial for solving the problem. There is also a discussion about the calculations leading to incorrect values, indicating potential misunderstandings in applying the formulas.

shad0w0f3vil
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Hi there,

I received this question with regards to planetary (or in this case satellite) motion:

Determine at what height above the Earth an arteficial satellite must orbit if it is to remain in the same place relative to the Earth (Hint: Model the situation using Kepler's Laws of Motion).

I believe that both the second and third laws are not applicable for this question, meaing the first law should be used. I am just unsure of how to 'start' it off.

Any help with this would be greatly appreciated.
 
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The third law is the only one that matters. What is it? Why can't you use it?
 
I thought I didnt have enough information. For example I do not know the period
 
shad0w0f3vil said:
I thought I didnt have enough information. For example I do not know the period

If it remains in the same place relative to the earth, it must go around the Earth in the same time it takes the Earth to rotate. I.e. it's period must be 24 hours.
 
ok so how do i work out my distance from the Earth then? or do i work with respect to the sun?

Just that when I try it i end up with the average distance being equal to 0km, which obviously is not correct
 
hold that thought, I managed to get a different answer from 0. I got, 6,380,000km.

any ideas on this value?
 
shad0w0f3vil said:
hold that thought, I managed to get a different answer from 0. I got, 6,380,000km.

any ideas on this value?

Yes. They are both way wrong. Could you show us the equation you are using and the numbers you are plugging into it?
 
Hint: [tex]T^2=\frac{4\pi r^3}{GM}[/tex]

M is the mass of earth...
 

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