Geosynchronous Satellite Height & Speed Calc.

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SUMMARY

A geosynchronous satellite must orbit at a height of approximately 35,786 kilometers above the Earth's surface to maintain a fixed position relative to the equator. The gravitational force equation, Fg = GM1M2/r^2, is essential for calculating the satellite's required speed and height. By applying Kepler's Third Law, T1^2/R1^3 = T2^2/R2^3, where T1 is the moon's orbital period and T2 is the satellite's orbital period, one can derive the necessary orbital radius. The final calculations yield the satellite's speed and confirm its geosynchronous nature.

PREREQUISITES
  • Understanding of gravitational force equations, specifically Fg = GM1M2/r^2
  • Familiarity with Kepler's Third Law of planetary motion
  • Basic knowledge of circular motion and centripetal acceleration
  • Concept of angular speed in relation to Earth's rotation
NEXT STEPS
  • Research the derivation of Kepler's Third Law for different celestial bodies
  • Learn about the physics of satellite motion and orbital mechanics
  • Explore gravitational potential energy and its implications for satellite placement
  • Study the effects of atmospheric drag on satellite orbits
USEFUL FOR

Astronomy students, physics enthusiasts, aerospace engineers, and anyone interested in satellite technology and orbital dynamics.

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Homework Statement



A geosynchronous satellite is one that stays above the same point on the equator of the earth.
Determine the height above the Earth's surface such a satellite must orbit and find it's speed.

Homework Equations


Fg = GM1M2/r^2

The Attempt at a Solution



I really don't know where to start, but I thought that maybe I could use the T1^2/R1^3 = T2^2/R2^3 Where T1 = The time period of the moon and T2 = is the time period of the satellite. I don't know if we're suppose to know the distance of the moon to the Earth. Someone please help. My teacher can't teach.
 
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DeeNoo said:

Homework Statement



A geosynchronous satellite is one that stays above the same point on the equator of the earth.
Determine the height above the Earth's surface such a satellite must orbit and find it's speed.

Homework Equations


Fg = GM1M2/r^2

The Attempt at a Solution



I really don't know where to start, but I thought that maybe I could use the T1^2/R1^3 = T2^2/R2^3 Where T1 = The time period of the moon and T2 = is the time period of the satellite. I don't know if we're suppose to know the distance of the moon to the Earth. Someone please help. My teacher can't teach.
Follow these four steps:

1. What is the force (gravity) on a satellite of mass m at a distance r from the Earth's centre?
2. What is the (centripetal) acceleration of a satellite prescribing a circular orbit of radius r (ie. from the Earth's centre)?
3. How are 1 and 2 related?
4. Now, suppose that the angular speed of the satellite is the same as the angular speed of the Earth's rotation about its axis and solve for r. Then work out what that is in terms of distance from the surface of the earth.

AM
 

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